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प्रश्न
Display electron distribution around the oxygen atom in the water molecule and state the shape of the molecule, also write the H-O-H bond angle.
उत्तर
Electron distribution around oxygen atom in water molecule:
Shape of water molecule: Angular or V-shaped
H–O–H bond angle = 104°35’
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संबंधित प्रश्न
Draw diagram for bonding in ethene with sp2 Hybridisation.
Draw an orbital diagram of Fluorine molecule
Distinguish between sigma and pi bond.
Give reasons for need of Hybridization
Complete the following Table.
| Molecule | Type of Hybridization | Type of bonds | Geometry | Bond angle |
| CH4 | - | 4C-H 4σ bonds |
Tetrahedral | - |
| NH3 | sp3 | 3N-H 3σ bonds 1 lone pair |
- | - |
| H2O | - | - | angular | 104.5° |
| BF3 | sp2 | - | - | 120° |
| C2H4 | - | - | - | 120° |
| BeF2 | - | 2 Be-F | Linear | - |
| C2H2 | sp | (3σ+2π) 1C-C σ 2C-H σ 2C-C π |
- | - |
Give the type of overlap by which the pi (π) bond is formed.
Which one of the following is the likely bond angles of sulphur tetrafluoride molecule?
According to Valence bond theory, a bond between two atoms is formed when ______.
When ones and three p orbitals hybridise,
Which of these represents the correct order of their increasing bond order.
Which bond is stronger σ or π? Why?
Considering x-axis as the molecular axis which out of the following will form a sigma bond.
1s and 2py
Considering x-axis as the molecular axis which out of the following will form a sigma bond.
1s and 2pz
Which of the following is correct decreasing order of the repulsive Interaction of electron pairs in a molecule?
The number of sigma bonds in vanillin is ____________.
If the electronic configuration of an element is 1s2 2s2 2p6 3s2 3p6 3d2 4s2, the four electrons involved in chemical bond formation will be ______.
Why does type of overlap given in the following figure not result in bond formation?
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Match List - I with List - II.
| List - I | List - II | ||
| (a) | \[\ce{PCl5}\] | (i) | Square pyramidal |
| (b) | \[\ce{SF6}\] | (ii) | Trigonal planar |
| (c) | \[\ce{BrF5}\] | (iii) | Octahedral |
| (d) | \[\ce{BF3}\] | (iv) | Trigonal bipyramidal |
Choose the correct answer from the options given below.
The \[\ce{H - N - H}\] bond angle in ammonia molecule is ______.
