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प्रश्न
Display electron distribution around the oxygen atom in the water molecule and state the shape of the molecule, also write the H-O-H bond angle.
उत्तर
Electron distribution around oxygen atom in water molecule:
Shape of water molecule: Angular or V-shaped
H–O–H bond angle = 104°35’
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संबंधित प्रश्न
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| List - I | List - II | ||
| (a) | \[\ce{PCl5}\] | (i) | Square pyramidal |
| (b) | \[\ce{SF6}\] | (ii) | Trigonal planar |
| (c) | \[\ce{BrF5}\] | (iii) | Octahedral |
| (d) | \[\ce{BF3}\] | (iv) | Trigonal bipyramidal |
Choose the correct answer from the options given below.
