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प्रश्न
Draw the graphs of the following linear equations:
3x + 2y - 6 = 0
उत्तर
3x + 2y - 6 = 0
⇒ 3x + 2y = 6
⇒ 2y = 6 - 3x
⇒ y = `(6 - 3x)/(2)`
Corresponding values of x and y can be tabulated as follows :
| X | 0 | 1 | -1 |
| Y | 3 | 1.5 | 4.5 |
Plotting the points (0, 3), (1, 1.5) and (-1, 4.5),
we get the following graph :
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संबंधित प्रश्न
Draw the graph of the following linear equation in two variable : –x + y = 6
Draw the graph for the equation, given below :
x = 5
Draw the graph for the equation, given below :
y = 7
Use the table given below to draw the graph.
| X | - 5 | - 1 | 3 | b | 13 |
| Y | - 2 | a | 2 | 5 | 7 |
From your graph, find the values of 'a' and 'b'.
State a linear relationship between the variables x and y.
Solve, graphically, the following pairs of equation :
x - 5 = 0
y + 4 = 0
Use graph paper for this question. Take 2 cm = 1 unit on both the axes.
- Draw the graphs of x + y + 3 = 0 and 3x - 2y + 4 = 0. Plot only three points per line.
- Write down the coordinates of the point of intersection of the lines.
- Measure and record the distance of the point of intersection of the lines from the origin in cm.
By drawing a graph for each of the equations 3x + y + 5 = 0; 3y - x = 5 and 2x + 5y = 1 on the same graph paper; show that the lines given by these equations are concurrent (i.e. they pass through the same point). Take 2 cm = 1 unit on both the axes.
Using a scale of 1 cm to 1 unit for both the axes, draw the graphs of the following equations: 6y = 5x + 10, y = 5x - 15.
From the graph find :
(i) the coordinates of the point where the two lines intersect;
(ii) the area of the triangle between the lines and the x-axis.
Every point on the graph of a linear equation in two variables does not represent a solution of the linear equation.
Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units.
