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प्रश्न
Expand.
`(2m + 1/5)^3`
उत्तर
Here, a = 2m, b = `1/5`
We know that,
(a + b)3 = a3 + 3a2b + 3ab2 + b3
∴ `(2m + 1/5)^3 = (2m)^3 + 3(2m)^2(1/5) + 3(2m)(1/5)^2 + (1/5)^3`
= `2^3m^3 + 3/5(2^2 m^2) + 6m xx 1^2/5^2 + 1^3/5^3`
= `8m^3 + 12/5 m^2 + (6m)/25 + 1/125`
∴ `(2m + 1/5)^3 = 8m^3 + 12/5 m^2 + 6/25m + 1/125`
संबंधित प्रश्न
If a + 2b = 5; then show that : a3 + 8b3 + 30ab = 125.
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
(i) Sum of these numbers
(ii) Difference of their cubes
(iii) Sum of their cubes.
Expand : (3x + 5y + 2z) (3x - 5y + 2z)
Find the cube of: `4"p" - (1)/"p"`
If p - q = -1 and pq = -12, find p3 - q3
If x + 2y = 5, then show that x3 + 8y3 + 30xy = 125.
Simplify:
(a + b)3 + (a - b)3
Expand: `((2m)/n + n/(2m))^3`.
Expand (2a + 5)3
Expand (52)3
