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प्रश्न
Expand : `( x - 1/x + 5)^2`
बेरीज
उत्तर
`( x - 1/x + 5)^2 = (x)^2 + (1/x)^2 + (5)^2 - 2(x)(1/x) - 2(1/x)(5) + 2(5)(x)`
=`x^2 + 1/x^2 + 25 - 2 - 10/x + 10x`
=`x^2 + 1/x^2 + 23 - 10/x + 10x`
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