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Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88° - Mathematics

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प्रश्न

Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°

बेरीज

उत्तर

cos72° - cos88°
= cos(90° - 18°) - cos(90° - 2°)
= sin18° - sin2°.

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Trigonometric Equation Problem and Solution
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.3

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फ्रँक Mathematics [English] Class 9 ICSE
पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.3 | Q 4.2
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