Express Log102 + 1 in the Form of Log10x. - Mathematics

Express log₁₀2 + 1 in the form of log₁₀x .

बेरीज

log₁₀2 + 1

= log₁₀2 + log₁₀10 ....[ ∵ log₁₀10 = 1 ]

= log₁₀2 x 10 ....[ log_am + log_an = log_amn ]

= log₁₀20.

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Laws of Logarithm

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पाठ 8: Logarithms - Exercise 8 (B) [पृष्ठ १०६]

पाठ 8 Logarithms
Exercise 8 (B) | Q 6 | पृष्ठ १०६

Express in terms of log 2 and log 3:

log 144

Express in terms of log 2 and log 3 :
`"log"26/51 - "log"91/119`

Evaluate the following without using tables :
log 4 + `1/3` log 125 - `1/5`log 32

Solve for x : log (x - 2) + log (x + 2) = log 5

Solve for x : `(log 81)/(log27 )` = x

If log 2 = 0.3010 and log 3 = 0.4771; find the value of:

`2/3` log 8

Solve for x : ` (log 64)/(log 8)` = log x

State, true or false :
`log x/log y` = log x - log y

State, true or false :
log x x log y = log x + log y

Given that log x = m + n and log y = m - n, express the value of log ` ( 10x ) / ( y ^ 2 )` in terms of m and n.