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Find the Distance Between the Points P and Q Having Coordinates (–2, 3, 1) and (2, 1, 2). - Mathematics

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प्रश्न

Find the distance between the points P and Q having coordinates (–2, 3, 1) and (2, 1, 2).

उत्तर

PQ = \[\sqrt{\left( x_2 - x_1 \right)^2 + \left( y_2 - y_1 \right)^2 + \left( z_2 - z_1 \right)^2}\]

\[= \sqrt{\left( 2 + 2 \right)^2 + \left( 1 - 3 \right)^2 + \left( 2 - 1 \right)^2}\]
\[ = \sqrt{\left( 4 \right)^2 + \left( - 2 \right)^2 + \left( 1 \right)^2}\]
\[ = \sqrt{16 + 4 + 1}\]
\[ = \sqrt{21} \text{ units }\]

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पाठ 28: Introduction to three dimensional coordinate geometry - Exercise 28.2 [पृष्ठ ९]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 28 Introduction to three dimensional coordinate geometry
Exercise 28.2 | Q 2 | पृष्ठ ९

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