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Question
Find the distance between the points P and Q having coordinates (–2, 3, 1) and (2, 1, 2).
Solution
PQ = \[\sqrt{\left( x_2 - x_1 \right)^2 + \left( y_2 - y_1 \right)^2 + \left( z_2 - z_1 \right)^2}\]
\[= \sqrt{\left( 2 + 2 \right)^2 + \left( 1 - 3 \right)^2 + \left( 2 - 1 \right)^2}\]
\[ = \sqrt{\left( 4 \right)^2 + \left( - 2 \right)^2 + \left( 1 \right)^2}\]
\[ = \sqrt{16 + 4 + 1}\]
\[ = \sqrt{21} \text{ units }\]
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