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Find the shortest distance between the lines given by r→=(8+3λi^-(9+16λ)j^+(10+7λ)k^ and r→=15i^+29j^+5k^+μ(3i^+8j^-5k^) - Mathematics

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Question

Find the shortest distance between the lines given by `vecr = (8 + 3lambdahati - (9 + 16lambda)hatj + (10 + 7lambda)hatk` and `vecr = 15hati + 29hatj + 5hatk + mu(3hati + 8hatj - 5hatk)`

Sum

Solution

We have `vecr = (8 + 3lambdahati - (9 + 16lambda)hatj + (10 + 7lambda)hatk`

= `8hati + 9hatj + 10hatk + lambda(3hati - 16hatj + 7hatk)`

⇒ `veca_1 = 8hati - 9hatj + 10hatk` and `vecb_1 = 3hati - 16hatj + 7hatk`  .....(i)

Aslo `vecr = 15hati + 29hatj + 5hatk + mu(3hati + 8hatj - 5hatk)`

⇒ `veca_2 = 15hati + 29hatj + 5hatk` and `vecb_2 = 3hati + 8hatj - 5hatk`  .....(ii)

Now, shortest distance between two lines is given by

`|((vecb_1 xx vecb_2) * (veca_2 - veca_2))/|vecb_1 xx vecb_2||`

∴ `vecb_1 xx vecb_2 = |(hati, hatj, hatk),(3, -16, 7),(3, 8, -5)|`

= `hati(80 - 56) - hatj(-15 - 21) + hatk(24 + 48)`

= `24hati + 36hatj + 72hatk`

⇒ `|vecb_1 xx vecb_2| = sqrt(24^2 + 36^2 + 72^2)`

= `12sqrt(2^2 + 3^2 + 6^2)`

= 84

Now `(veca_2 - veca_1) = (15 - 8)hati + (29 + 9)hatj + (5 - 10)hatk`

= `7hati + 38hatj - 5hatk`

∴ Shortest distance = `|((24hati + 36hatj + 72hatk) * (7hati + 38hatj - 5hatk))/84|`

= `|((2hati + 3hatj + 6hatk) * (7hati + 38hatj - 5hatk))/7|`

= `|(14 + 114 - 30)/7|`

= 14

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Chapter 12: Introduction to Three Dimensional Geometry - Exercise [Page 237]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Exercise | Q 21 | Page 237

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