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Find the Probability that the Sum of the Numbers Showing on Two Dice is 8, Given that at Least One Die Does Not Show Five. - Mathematics

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प्रश्न

Find the probability that the sum of the numbers showing on two dice is 8, given that at least one die does not show five.

उत्तर

Consider the given events.
A = At least one die does not show 5
B = The sum of the numbers on two dice is 8.

Clearly,
A = {(1, 1), (1, 2) (1, 3), (1, 4),(1, 6),(2, 1), (2, 2) (2, 3), (2, 4), (2, 6), (3, 1), (3, 2), (3, 3) (3, 4), (3, 6),(4, 1), (4, 2), (4, 3), (4, 4), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 6)}
B = {(2, 6), (3, 5), (4, 4), (5, 3),(6, 2)}

\[\text{ Now } , \]

\[A \cap B = \left\{ \left( 4, 4 \right), \left( 6, 2 \right), \left( 2, 6 \right) \right\}\]

\[ \therefore \text{ Required probability } = P\left( B/A \right) = \frac{n\left( A \cap B \right)}{n\left( A \right)} = \frac{3}{25}\]

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Probability Examples and Solutions
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पाठ 31: Probability - Exercise 31.3 [पृष्ठ ३५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 31 Probability
Exercise 31.3 | Q 18 | पृष्ठ ३५

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