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प्रश्न
Find the area of the shaded field shown in figure.
उत्तर
In a figure, join ED
From figure, radius of semi-circle DEF, r = 6 – 4 = 2 m
Now, area of rectangle ABCD = BC × AB = 8 × 4 = 32 cm2
And area of semi-circle DFE = `(π"r"^2)/2 = π/2 (2)^2` = 2π m2
∴ Area of shaded region = Area of rectangle ABCD + Area of semi-circle DFE
= (32 + 2π) m2
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Read the following passage:
Governing council of a local public development authority of Dehradun decided to build an adventurous playground on the top of a hill, which will have adequate space for parking. After survey, it was decided to build rectangular playground, with a semi-circular area allotted for parking at one end of the playground. The length and breadth of the rectangular playground are 14 units and 7 units, respectively. There are two quadrants of radius 2 units on one side for special seats. |
Based on the above information, answer the following questions:
- What is the total perimeter of the parking area?
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OR
(b) What is the ratio of area of playground to the area of parking area? - Find the cost of fencing the playground and parking area at the rate of ₹ 2 per unit.
