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प्रश्न
Find the area of the triangle whose vertices are (–8, 4), (–6, 6) and (–3, 9).
उत्तर
Given that, the vertices of triangles are (–8, 4), (–6, 6) and (–3, 9).
Let (x1, y1) `→` (−8, 4)
(x2, y2) `→` (−6, 6)
And (x3, y3) `→` (−3, 9)
We know that, the area of triangle with vertices
(x1, y1), (x2, y2) and (x3, y3)
Δ = `1/2[x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]`
= `1/2[-8(6 - 9) - 6(9 - 4) + (-3)(4 - 6)]`
= `1/2[-8(-3) - 6(5) - 3(-2)]`
= `1/2(24 - 30 + 6)`
= `1/2(30 - 30)`
= `1/2(0)`
= 0
Hence, the required area of triangle is 0.
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