Advertisements
Advertisements
प्रश्न
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
उत्तर
`((2"m")/(3"n") + (3"n")/(2"m"))^3`
= `((2"m")/(3"n"))^3 + ((3"n")/(2"m"))^3 + 3((2"m")/(3"n"))((3"n")/(2"m"))((2"m")/(3"n") + (3"n")/(2"m"))`
= `(8"m"^3)/(27"n"^3) + (27"n"^3)/(8"m"^3) + (2"m")/"n" + (9"n")/(2"m")`.
APPEARS IN
संबंधित प्रश्न
Expand.
(52)3
Simplify.
(3r − 2k)3 + (3r + 2k)3
If a + 2b = 5; then show that : a3 + 8b3 + 30ab = 125.
If 4x2 + y2 = a and xy = b, find the value of 2x + y.
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
(i) Sum of these numbers
(ii) Difference of their cubes
(iii) Sum of their cubes.
If X ≠ 0 and X + `1/"X"` = 2 ; then show that :
`x^2 + 1/x^2 = x^3 + 1/x^3 = x^4 + 1/x^4`
Find the cube of: 2a - 5b
Find the cube of: `"a" - (1)/"a" + "b"`
If m - n = -2 and m3 - n3 = -26, find mn.
Expand: (3x + 4y)3.
