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प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 160°
उत्तर
Let no.of.sides of regular polygon be n.
Each interior angle = 160°
`therefore ("n" - 2)/"n" xx 180^circ = 160^circ`
180n - 360° = 160n
180n - 160n = 360°
20n = 360°
n = 18
संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
Is it possible to have a regular polygon whose interior angle is : 170°
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(i) measure of each interior angle ;
(ii) measure of each exterior angle and
(iii) number of sides in the polygon.
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(ii) its each exterior angle
(iii) the number of sides in the polygon.
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
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