Advertisements
Advertisements
प्रश्न
Find the slope and y-intercept of the line:
3x – 4y = 5
उत्तर
3x − 4y = 5
`=>` 4y = 3x – 5
`=> y = 3/4 x - 5/4`
Comparing this equation with y = mx + c, we have:
Slope = m = `3/4`
y-intercept = c =`(-5)/4`
APPEARS IN
संबंधित प्रश्न
A (5, 4), B (-3, -2) and C (1, -8) are the vertices of a triangle ABC. Find the equations of the median AD and line parallel to AC passing through the point B.
In ΔABC, A(3, 5), B(7, 8) and C(1, –10). Find the equation of the median through A.
B(−5, 6) and D(1, 4) are the vertices of rhombus ABCD. Find the equations of diagonals BD and AC.
- Write down the equation of the line AB, through (3, 2) and perpendicular to the line 2y = 3x + 5.
- AB meets the x-axis at A and the y-axis at B. Write down the co-ordinates of A and B. Calculate the area of triangle OAB, where O is the origin.
The point P is the foot of perpendicular from A(−5, 7) to the line whose equation is 2x – 3y + 18 = 0. Determine :
- the equation of the line AP.
- the co-ordinates of P.
Find the point on the X–axis which is equidistant from A(–3, 4) and B(1, –4).
In Δ DEF, line PQ || side EF, If DP = 2.4,
PE = 7.2, DQ = 1 then find QF.
A line through point P(4, 3) meets x-axis at point A and the y-axis at point B. If BP is double of PA, find the equation of AB.
Three vertices of a parallelogram ABCD taken in order are A(3, 6), B(5, 10) and C(3, 2), find:
- the co-ordinates of the fourth vertex D.
- length of diagonal BD.
- equation of side AB of the parallelogram ABCD.
A line segment joining P(2, –3) and Q(0, –1) is cut by the x-axis at the point R. A line AB cuts the y-axis at T(0, 6) and is perpendicular to PQ at S.
Find the:
- equation of line PQ
- equation of line AB
- coordinates of points R and S.