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प्रश्न
Generally transition elements form coloured salts due to the presence of unpaired electrons. Which of the following compounds will be coloured in solid-state?
पर्याय
\[\ce{Ag2SO4}\]
\[\ce{CuF2}\]
\[\ce{ZnF2}\]
\[\ce{Cu2Cl2}\]
उत्तर
\[\ce{CuF2}\]
Explanation:
\[\ce{Cu^{2+}}\] has 1 unpaired electron in \[\ce{CuF2}\], hence, it is coloured in solid state.
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संबंधित प्रश्न
Why is Sc3+ colourless while Ti3+ coloured? (Atomic number Sc = 21, Ti =22)
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Assertion: \[\ce{Cu}\] cannot liberate hydrogen from acids.
Reason: Because it has positive electrode potential.
Match List - I with List - II
List - I | List - II | ||
(a) | \[\ce{[Fe(CN)6]^3-}\] | (i) | 5.92 BM |
(b) | \[\ce{[Fe(H2O)6]^3+}\] | (ii) | 0 BM |
(c) | \[\ce{[Fe(CN)6]^4-}\] | (iii) | 4.90 BM |
(d) | \[\ce{[Fe(H2O)6]^2+}\] | (iv) | 1.73 BM |
Choose the correct answer from the options given below.
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Why are interstitial compounds well known for transition metals?