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प्रश्न
Give reasons for the following observation:
pKb of aniline is lower than the m-nitroaniline.
उत्तर
pKb of aniline is lower than the m-nitro aniline.The basic strength of aniline is more than m-nitroaniline. pKb value is inversely proportional to basic strength. The presence of an Electron withdrawing group decreases basic strength.
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संबंधित प्रश्न
Arrange the following:
Aniline, p-nitroaniline, p-methylaniline - in the increasing order of their basic strength
Write the chemical equations involved when aniline is treated with the following reagents: HCI
Arrange the following:
In decreasing order of the pKb values:
C2H5NH2, C6H5NHCH3, (C2H5)2NH and C6H5NH2
Arrange the following:
In decreasing order of basic strength in the gas phase:
C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3
The following reaction takes place in the presence of:
Arrange the following in decreasing order of their basic strength:
C6H5NH2, C2H5NH2, (C2H5)2NH2, NH3
Explain why \[\ce{MeNH2}\] is stronger base than \[\ce{MeOH}\]?
Account for the following:
Arrange the following compounds in the increasing order of their basic strength in aqueous solution: CH3NH2,(CH3)3N,(CH3)2NH
Arrange the decreasing order of pKb values.
\[\ce{C6H5NH2, C6H5NHCH3, C6H5CH2NH2, CH3NH2, NH3}\]
The correct order of the increasing basic nature of Ammonia, Methylamine and Aniline is:
