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प्रश्न
Given that `tan (θ_1 + θ_2) = (tan θ_1 + tan θ_2)/(1 - tan θ_1 tan θ_2)` Find (θ1 + θ2) when tan θ1 = `1/2 and tan θ_2 = 1/3`.
उत्तर
We have,
tan θ1 = `1/2 and tan θ_2 = 1/3`
∴ `tan (θ_1 + θ_2) = (tan θ_1 + tan θ_2)/(1 - tan θ_1 tan θ_2)`
= `(1/2 + 1/3)/(1 - 1/2 xx 1/3)`
= `(5/6)/(1 - 1/6)`
= `tan (θ_1 + θ_2) = (5/6)/(5/6)`
= tan (θ1 + θ2) = 1
= θ1 + θ2 = 45°
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