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If A= `[[3 -2],[4 -2]]` And I= `[[1 0],[0 1]]` Then Prove That A2 − A + 2i = O. - Mathematics

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प्रश्न

\[A = \begin{bmatrix}3 & - 2 \\ 4 & - 2\end{bmatrix} and \text{ I }= \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}\],  then prove that A2 − A + 2I = O.

बेरीज

उत्तर

\[Given: \hspace{0.167em} A = \begin{bmatrix}3 & - 2 \\ 4 & - 2\end{bmatrix}\]
\[Now, \]
\[ A^2 = AA\]
\[ \Rightarrow A^2 = \begin{bmatrix}3 & - 2 \\ 4 & - 2\end{bmatrix}\begin{bmatrix}3 & - 2 \\ 4 & - 2\end{bmatrix}\]
\[ \Rightarrow A^2 = \begin{bmatrix}9 - 8 & - 6 + 4 \\ 12 - 8 & - 8 + 4\end{bmatrix}\]
\[ \Rightarrow A^2 = \begin{bmatrix}1 & - 2 \\ 4 & - 4\end{bmatrix}\]
\[ A^2 - A + 2I = \begin{bmatrix}1 & - 2 \\ 4 & - 4\end{bmatrix} - \begin{bmatrix}3 & - 2 \\ 4 & - 2\end{bmatrix} + 2\begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}\]
\[ \Rightarrow A^2 - A + 2I = \begin{bmatrix}1 - 3 & - 2 + 2 \\ 4 - 4 & - 4 + 2\end{bmatrix} + \begin{bmatrix}2 & 0 \\ 0 & 2\end{bmatrix}\]
\[ \Rightarrow A^2 - A + 2I = \begin{bmatrix}- 2 & 0 \\ 0 & - 2\end{bmatrix} + \begin{bmatrix}2 & 0 \\ 0 & 2\end{bmatrix}\]
\[ \Rightarrow A^2 - A + 2I = \begin{bmatrix}- 2 + 2 & 0 + 0 \\ 0 + 0 & - 2 + 2\end{bmatrix}\]
\[ \Rightarrow A^2 - A + 2I = \begin{bmatrix}0 & 0 \\ 0 & 0\end{bmatrix}\]
\[ \Rightarrow A^2 - A + 2I = 0\]
Hence proved .

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पाठ 5: Algebra of Matrices - Exercise 5.3 [पृष्ठ ४३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 5 Algebra of Matrices
Exercise 5.3 | Q 27 | पृष्ठ ४३

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