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प्रश्न
Compute the elements a43 and a22 of the matrix:`A=[[0 1 0],[2 0 2],[0 3 2],[4 0 4]]` `[[2 -1],[-3 2],[4 3]] [[0 1 -1 2 -2],[3 -3 4 -4 0]]`
उत्तर
We have,
Given `A=[[0 1 0],[2 0 2],[0 3 2],[4 0 4]]` `[[2 -1],[-3 2],[4 3]] [[0 1 -1 2 -2],[3 -3 4 -4 0]]`
`⇒A= [[0 1 0],[2 0 2],[0 3 2],[4 0 4]]` `[[0-3 2+3 -2-4 4+4 -4-0],[0+6 -3-6 3+8 -6-8 6+0],[0+9 4-9 -4+12 8-12 -8+0]]`
`⇒A= [[0 1 0],[2 0 2],[0 3 2],[4 0 4]]` `[[-3 5 -6 8 -4],[6 -9 11 -14 6],[9 -5 8 -4 -8]]`
`⇒ A= [[0+6+0 0-9-0 0+11+0 0-14-0 0+6-0],[-6+0+18 10-0-10 -12+0+16 16-0-8 -8+0-16],[0+18+18 0-27-10 0+33+16 0-42-8 0+18-16],[-12+0+36 20-0-20 -24+0+32 32-0-16 -16+0-32]]`
`⇒ A = [[6 -9 11 -14 6],[12 0 4 8 -24],[36 -37 49 -50 2],[24 0 8 16 -48]]`
∴ `a_43` =8 and `a_22` =0
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