Advertisements
Advertisements
प्रश्न
If one of the roots of quadratic equation x2 + kx + 54 = 0 is – 6, then complete the following activity to find the value of ‘k’.
Activity: One of the roots of the quadratic equation x2 + kx + 54 = 0 is – 6.
Therefore let’s take x = ______
(– 6)2 + k(– 6) + 54 = 0
(______) – 6k + 54 = 0
– 6k + ______ = 0
k = ______
उत्तर
One of the roots of the quadratic equation x2 + kx + 54 = 0 is – 6.
Therefore let’s take x = − 6
∴ (– 6)2 + k(– 6) + 54 = 0
∴ 36 – 6k + 54 = 0
∴ – 6k + 90 = 0
∴ 6k = 90
∴ k = `90/6`
∴ k = 15
APPEARS IN
संबंधित प्रश्न
If the roots of 2x2 - 6x + k = 0 are real and equal, find k.
Solve : 7y = -3y2 - 4
Form the quadratic equation if the roots are 3 and 8.
If one root of the quadratic, x2 - 7x + k = 0 is 4. then find the value of k.
Form the quadratic equation if its roots are 5 and 7.
Choose the correct alternative answer for the following sub-questions and write the correct alphabet.
Which of the following quadratic equation has roots – 3 and – 5?
Roots of a quadratic equation are 5 and – 4, then form the quadratic equation
If the roots of the given quadratic equation are real and equal, then find the value of ‘k’
kx(x – 2) + 6 = 0
Solve the following quadratic equations by formula method.
`y^2 + 1/3y` = 2
Form a quadratic equation if the roots of the quadratic equation are `2 + sqrt(7)` and `2 - sqrt(7)`
Solve the following quadratic equation.
`1/(4 - "p") - 1/(2 + "p") = 1/4`
Sum of the roots of the quadratic equation is 5 and sum of their cubes is 35, then find the quadratic equation
Solve the following quadratic equation using formula:
x2 + 10x + 2 = 0
Determine whether (x – 3) is a factor of polynomial x3 – 19x + 30.
Let P(x) = x3 – 19x + 30
By remainder theorem, `square` will be a factor of P(x), if P(3) = 0
Now, P(3) = `square` – 19 `square` + 30
= `square – square` + 30
= `square – square`
= 0
∵ P(3) = 0
Hence, `square` is a factor of polynomial x3 – 19x + 30.
Is (x – 5) a factor of the polynomial x3 – 5x – 30?
One of the roots of equation x2 + 5x + a = 0 is – 3. To find the value of a, fill in the boxes.
Since, `square` is a root of equation x2 + 5x + a = 0
∴ Put x = `square` in the equation
⇒ `square^2 + 5 xx square + a` = 0
⇒ `square + square + a` = 0
⇒ `square + a` = 0
⇒ a = `square`
If 3 is one of the roots of the quadratic equation kx2 − 7x + 12 = 0, then k = ______.