Advertisements
Advertisements
प्रश्न
If the quadratic equation x2 + 4x + k = 0 has real and equal roots, then ______.
पर्याय
k < 4
k > 4
k = 4
k ≥ 4
उत्तर
If the quadratic equation x2 + 4x + k = 0 has real and equal roots, then k = 4.
Explanation:
x2 + 4x + k = 0
Discriminant = 0
b2 – 4ac = 0
16 – 4(1)(k) = 0
16 – 4k = 0
`\cancel–` 4k = `\cancel–` 16
k = `16/4`
k = 4
APPEARS IN
संबंधित प्रश्न
If the roots of the equation (a2 + b2) x2 – 2(ac + bd) x + (c2 + d2) = 0 are equal, prove that `a/b = c/d`
Write the discriminant of the following quadratic equations:
4x2 - 3kx + 1 = 0
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
`sqrt2x^2+7x+5sqrt2=0`
Find the roots of the each of the following equations, if they exist, by applying the quadratic formula:
`x^2-4x-1=0`
`x^2-6x+4=0`
`3a^2x^2+8abx+4b^2=0`
`12abx^2-(9a^2-8b^2)x-6ab=0,` `Where a≠0 and b≠0`
Find the nature of roots of the following quadratic equations:
`x^2-x+2=0`
Find the value of p for which the quadratic equation `(2p+1)x^2-(7p+2)x+(7p-3)=0` has real and equal roots.
If -4 is a root of the equation `x^2+2x+4p=0` find the value of k for the which the quadratic equation ` x^2+px(1+3k)+7(3+2k)=0` has equal roots.