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प्रश्न
In the given figure, ABCD is a trapezium of area 24.5 cm2 , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region.
उत्तर
Area of trapezium `=1/2("AD" + "BC")xx"AB"`
`=>24.5 = 1/2(10+4)xx"AB"`
⇒ AB = 3.5 cm
Area of shaded region = Area of trapezium ABCD − Area of quadrant ABE
`= 24.5 - 1/4pi("AB")^2`
`= 24.5-1/4xx22/7(3.5)^2`
= 24.5- 9.625
= 14.875 cm2
Hence, the area of shaded region is 14.875 cm2
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