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प्रश्न
In the adjoining diagram, O is the centre of the circle and PT is a tangent. The value of x is ______.
पर्याय
20°
40°
55°
70°
उत्तर
In the adjoining diagram, O is the centre of the circle and PT is a tangent. The value of x is 20°.
Explanation:
Given:
- O is the center of the circle.
- PT is a tangent to the circle at point T.
When a tangent and a radius intersect at the point of tangency, the angle formed between the radius and the tangent is 90°. This is a key property of circles and tangents.
Let's analyze the situation step by step:
Step-by-Step Solution
1. Identify the key points and angles:
- O is the center.
- PT is the tangent.
- OT is the radius.
- ∠OTP = 90° because the radius and tangent are perpendicular at the point of tangency.
2. Determine the relationship involving z:
Suppose we have a triangle OTP, where T is the point of tangency. Let's consider an angle ∠OTP which is 90°, and we are given that x = 20°.
3. Use the properties of the right triangle:
Since ∠OTP = 90°, we can identify other angles in the triangle.
If there is another angle related to a in this problem, let's denote it as ∠TOP.
Assuming x is a part of the complementary angle
Let's assume x is related to ∠OTP.
- ∠OTP + ∠PTO + ∠TOP = 180° ...(Sum of angles in a triangle)
- Given ∠OTP = 90°, we have:
90° + ∠PTO + x = 180° - Simplifying:
∠PTO + x = 90° - Given x = 20°:
∠PTO + 20° = 90°
∠PTO + 70°
So, the given value x = 20° complements ∠PTO which results in a 70° angle to satisfy the conditions of the right triangle formed by the tangent and radius.
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