Advertisements
Advertisements
प्रश्न
In the figure, given alongside, AOB is a diameter of the circle and ∠AOC = 110°. Find ∠BDC.
उत्तर
Join AD.
Here, `∠ADC = 1/2 ∠AOC`
= `1/2xx 110^circ`
= 55°
(Angle at the centre is double the angle at the circumference subtended by the same chord)
Also, ∠ADB = 90°
(Angle in a semicircle is a right angle)
∴ ∠BDC = 90° – ∠ADC
= 90° – 55°
= 35°
APPEARS IN
संबंधित प्रश्न
The length of common chord of two intersecting circles is 30 cm. If the diameters of these two circles be 50 cm and 34 cm, calculate the distance between their centres.
In the figure, chords AE and BC intersect each other at point D. If ∠CDE = 90°, AB = 5 cm, BD = 4 cm and CD = 9 cm; find DE.
In the figure, AB is the chord of a circle with centre O and DOC is a line segment such that BC = DO. If ∠C = 20°, find angle AOD.
In the given figure, AB is the diameter. The tangent at C meets AB produced at Q.
If ∠CAB = 34°, Find : ∠CBA
Prove that the line segment joining the midpoints of two parallel chords of a circle passes through its centre.
Two circles are drawn with sides AB, AC of a triangle ABC as diameters. They intersect at a point D. Prove that D lies on BC.
Prove that the circle drawn on any one of the equal sides of an isosceles triangle as diameter bisects the base.
In following figure . O is the centre of the circle. Find ∠ BAC.
In following figure , chord ED is parallel to the diameter AC of the circle. Given ∠ CBE = 65° , calculate ∠DEC .
In the given figure, AB and CD are two equal chords of a circle, with centre O. If P is the mid-point of chord AB, Q is the mid-point of chord CD and ∠POQ = 150°, find ∠APQ.
