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प्रश्न
In the figure, given alongside, AOB is a diameter of the circle and ∠AOC = 110°. Find ∠BDC.
उत्तर
Join AD.
Here, `∠ADC = 1/2 ∠AOC`
= `1/2xx 110^circ`
= 55°
(Angle at the centre is double the angle at the circumference subtended by the same chord)
Also, ∠ADB = 90°
(Angle in a semicircle is a right angle)
∴ ∠BDC = 90° – ∠ADC
= 90° – 55°
= 35°
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