Advertisements
Advertisements
प्रश्न
In which of the following structures coordination number for cations and anions in the packed structure will be same?
पर्याय
Cl– ion form fcc lattice and Na+ ions occupy all octahedral voids of the unit cell.
Ca2+ ions form fcc lattice and F– ions occupy all the eight tetrahedral voids of the unit cell.
O2– ions form fcc lattice and Na+ ions occupy all the eight tetrahedral voids of the unit cell.
S2– ions form fcc lattice and Zn2+ ions go into alternate tetrahedral voids of the unit cell.
उत्तर
Cl– ion form fcc lattice and Na+ ions occupy all octahedral voids of the unit cell.
Explanation:
NaCl crystals have rock salt structure having fee lattice in which Cl– ions are present at fee lattice points and face centre and Na+ occupies all the octahedral voids of given unit cell.
Where, coordination number of Na+ = 6
APPEARS IN
संबंधित प्रश्न
What is the formula of a compound in which the element Y forms hcp lattice and atoms of X occupy 2/3rd of tetrahedral voids?
How will you distinguish between the following pairs of terms: Tetrahedral and octahedral voids
If the radius of the octachedral void is r and radius of the atoms in close packing is R, derive relation between r and R.
A compound is formed by two elements A and B. The element B forms cubic close packing and atoms of A occupy `1/3"rd"` of tetrahedral voids. The formula of this compound is ____________.
The Ca2+ and F– are located in CaF2 crystal, respectively at face centered cubic lattice points and in ____________.
In which of the following crystals alternate tetrahedral voids are occupied?
In the cubic close packing, the unit cell has ______.
The coordination number of Y will be in the XY types of crystal:
The number of tetrahedral voids per unit cell in NaCl crystal is:
(i) 4
(ii) 8
(iii) twice the number of octahedral voids.
(iv) four times the number of octahedral voids.
A solid compound XY has Nacl structure. If the radium of cation (X+) is 100 pm, the radium of anion (r–) will be:-
