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प्रश्न
Let `"A" = [(4 , -2),(6 , -3)], "B" = [(0 , 2),(1 , -1)] and "C" = [(-2 , 3),(1 , -1)]`. Find A2 - A + BC
उत्तर
`"A" = [(4 , -2),(6 , -3)], "B" = [(0 , 2),(1 , -1)] and "C" = [(-2 , 3),(1 , -1)]`.
∴ A2 = `[(4 , -2),(6 , -3)][(4 , -2),(6 , -3)]`
= `[(16 - 12, -8 +6),(24 - 18, -12 + 9)]`
∴ A2 = `[(4 , -2),(6 , -3)]`
BC = `[(0 , 2),(1 , -1)][(-2 , 3),(1 , -1)] = [(0 + 2 , 0 -2),(-2 - 1, 3 + 1)]`
= `[(2 , -2),(-3 , 4)]`
Now A2 - A + BC
= `[(4 , -2),(6 , -3)] - [(4 , -2),(6 , -3)] + [(2 , -2),(-3 , 4)]`
= `[(0 , 0),(0 , 0)] + [(2 , -2),(-3 , 4)] = [(2 , -2),(-3 , 4)]`
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