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प्रश्न
\[\lim_{x \to 0} \frac{e^{x + 2} - e^2}{x}\]
उत्तर
\[\lim_{x \to 0} \left[ \frac{e^{x + 2} - e^2}{x} \right]\]
\[ = \lim_{x \to 0} \left[ e^2 \left( \frac{e^x - 1}{x} \right) \right]\]
\[ = e^2 \times 1\]
\[ = e^2\]
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