Advertisements
Advertisements
प्रश्न
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the side along the road. It the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.
उत्तर
Perpendicular distance between two parallel sides = 100 m
Area of field = 10500 m2
Let the length of the side along the road = x
The length of the side along the river = 2x
Area of trapezium = 12 × (first side + second side) × perpendicular distance
10500 = `1/2` (x + 2x) × 100
10500 = 3x × 50
`x = 10500/(50×3)`
x = 70
Therefore, length of the side along the river = 2x
= 2 × 70
= 140 m
APPEARS IN
संबंधित प्रश्न
The floor of a building consists of 3000 tiles, which are rhombus shaped, and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if the cost per m2 is ₹ 4.
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?
The area of a rhombus is 240 cm2 and one of the diagonal is 16 cm. Find another diagonal.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.
Find the area of a rhombus, each side of which measures 20 cm and one of whose diagonals is 24 cm.
The length of a side of a square field is 4 m. what will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
In exchange of a square plot one of whose sides is 84 m, a man wants to buy a rectangular plot 144 m long and of the same area as of the square plot. Find the width of the rectangular plot.
Find the area of the following polygon, if AL = 10 cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.
Find the area of the following regular hexagon.
