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प्रश्न
PQ is a long straight conductor carrying a current of 3A as shown in Figure below. An electron moves with a velocity of 2 x 107 ms-1 parallel to it. Find the force acting on the electron.
उत्तर
q = 1.6 × 10-19 C, i=3 A, r = 0. 6 m
v = 2 x 107 ms-1
θ = 90°
`bar(B) = 10^-7 xx (2xx3)/0.6`
∴ Force on electron, \[\overrightarrow{F }\] = q v B sin θ
\[\overrightarrow{F }\] = 1.6 x 10-19 x 2 x 107 x 107. `6/0.6`
\[\overrightarrow{F }\]= 3.2 x 10-18 N
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