Advertisements
Advertisements
प्रश्न
Rationalise the denominator of the following:
`1/sqrt7`
उत्तर
The given number is `1/sqrt7`
On rationalising the denominator
⇒ `1/sqrt7 = 1/sqrt7 xx sqrt7/sqrt7`
∴ `1/sqrt7 = sqrt7/7`
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(11 + sqrt11)(11 - sqrt11)`
Simplify the following expressions:
`(2sqrt5 + 3sqrt2)^2`
Rationalise the denominator of the following
`(sqrt2 + sqrt5)/3`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
`(3 - sqrt5)/(3 + 2sqrt5)`
\[\sqrt{10} \times \sqrt{15}\] is equal to
Simplify the following expression:
`(sqrt5+sqrt2)^2`
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
