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प्रश्न
Reduce the equation\[\sqrt{3}\] x + y + 2 = 0 to intercept form and find intercept on the axes.
उत्तर
\[\sqrt{3}\] x + y + 2 = 0
\[\Rightarrow \sqrt{3}x + y = - 2\]
\[ \Rightarrow \frac{\sqrt{3}x}{- 2} + \frac{y}{- 2} = 1 \left[ \text { Dividing both sides by } - 2 \right]\]
\[ \Rightarrow \frac{x}{- \frac{2}{\sqrt{3}}} + \frac{y}{- 2} = 1\]
This is the intercept form of the given line.
Here, x-intercept = \[- \frac{2}{\sqrt{3}}\] and y-intercept = \[-\]2
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