मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Show that 9!3!6!+9!4!5!=10!4!6! - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Show that `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`

बेरीज

उत्तर

L.H.S. = `(9!)/(3!6!) + (9!)/(4!5!)`

= `(9!)/(3! xx 6 xx 5!) + (9!)/(4 xx 3! xx 5!)`

= `(9!)/(3!5!)[1/6 + 1/4]`

= `(9!)/(3!5!)[(4 + 6)/(6 xx 4)]`

= `(10 xx 9!)/(6 xx 5! xx 4 xx 3!)`

= `(10!)/(6!4!)`

= `(10!)/(4!6!)`

= R.H.S.

shaalaa.com
Factorial Notation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Permutations and Combination - Exercise 3.2 [पृष्ठ ५०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
पाठ 3 Permutations and Combination
Exercise 3.2 | Q 8 | पृष्ठ ५०

संबंधित प्रश्‍न

Evaluate: 8!


Evaluate: (10 – 6)!


Compute: 3! × 2!


Compute: `(9!)/(3!  6!)`


Compute: `(8!)/((6 - 4)!)`


Write in terms of factorial.

6 × 7 × 8 × 9


Write in terms of factorial.

5 × 10 × 15 × 20


Evaluate : `("n"!)/("r"!("n" - "r")!)` for n = 8, r = 6


Evaluate : `("n"!)/("r"!("n" - "r")!)` for n = 12, r = 12


Find n, if `"n"/(8!) = 3/(6!) + (1!)/(4!)`


Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`


Find n, if `(1!)/("n"!) = (1!)/(4!) - 4/(5!)`


Find n, if (n + 3)! = 110 × (n + 1)!


Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!


Find n, if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5 : 3


Find n, if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 7)!)` = 1 : 6


Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24 : 1


Show that `("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!)`


Show that `((2"n")!)/("n"!)` = 2n (2n – 1)(2n – 3) ... 5.3.1


Simplify `1/("n"!) - 1/(("n" - 1)!) - 1/(("n" - 2)!)`


Simplify n[n! + (n – 1)!] + n2(n – 1)! + (n + 1)!


Simplify `("n" + 2)/("n"!) - (3"n" + 1)/(("n" + 1)!)`


Simplify `1/(("n" - 1)!) + (1 - "n")/(("n" + 1)!)`


Select the correct answer from the given alternatives.

In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?


In how many ways can 10 examination papers be arranged so that the best and the worst papers never come together?


Select the correct answer from the given alternatives.

In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate


Eight white chairs and four black chairs are randomly placed in a row. The probability that no two black chairs are placed adjacently equals.


If `((11 - "n")!)/((10 - "n")!) = 9,`then n = ______.


3. 9. 15. 21 ...... upto 50 factors is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×