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प्रश्न
Solve for x:
`sqrt((8^0 + 2/3)` = (0.6)2-3x
बेरीज
उत्तर
`sqrt((8^0 + 2/3)` = (0.6)2-3x
⇒ `(1 + 2/3)^(1/2) = (6/10)^(2-3x)`
⇒ `(5/3)^(1/2) = (3/5)^(2-3x)`
⇒ `(3/5)^(-1/2) = (3/5)^(2-3x)`
⇒ `-(1)/(2)` = 2 - 3x
⇒ -1 = 4 - 6x
⇒ -5 = -6x
⇒ x = `(5)/(6)`.
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Solving Exponential Equations
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