मराठी

The Areas of Two Similar Triangles Are 169 Cm2 and 121 Cm2 Respectively. If the Longest Side of the Larger Triangle is 26 Cm, Find the Longest Side of the Smaller Triangle. - Mathematics

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प्रश्न

The areas of two similar triangles are 169 cm2 and 121 cm2 respectively. If the longest side of the larger triangle is 26 cm, find the longest side of the smaller triangle.

उत्तर

We have,

ΔABC ~ ΔPQR

Area(ΔABC) = 169 cm2

Area(ΔPQR) = 121 cm2

And AB = 26 cm

By area of similar triangle theorem

`("Area"(triangleABC))/("Area"(trianglePQR))="AB"^2/"PQ"^2`

`rArr169/121=26^2/"PQ"^2`

`rArr13/11=26/"PQ"`                     [Taking square root]

`rArr"PQ"=11/13xx26=22` cm

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पाठ 7: Triangles - Exercise 7.6 [पृष्ठ ९५]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 7 Triangles
Exercise 7.6 | Q 4 | पृष्ठ ९५

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