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प्रश्न
The line `(3x)/5 - (2y)/3 + 1 = 0` contains the point (m, 2m – 1); calculate the value of m.
उत्तर
The equation of the given line is `(3x)/5 - (2y)/3 + 1 = 0`
Putting x = m, y = 2m − 1, we have:
`(3m)/5 - (2(2m - 1))/3 + 1 = 0`
`(3m)/5 - (4m - 2)/3 + 1 = 0`
`(9m - 20m + 10)/15 = -1`
9m – 20m + 10 = –15
–11m = –25
`m = 25/11 = 2 3/11`
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