मराठी

The probability distribution of a discrete random variable X is given as under: X 1 2 4 2A 3A 5A P(X) 12 15 325 110 125 125 Calculate : Variance of X - Mathematics

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प्रश्न

The probability distribution of a discrete random variable X is given as under:

X 1 2 4 2A 3A 5A
P(X) `1/2` `1/5` `3/25` `1/10` `1/25` `1/25`

Calculate: Variance of X

तक्ता
बेरीज

उत्तर

Now the distribution becomes

X 1 2 4 6 9 15
P(X) `1/2` `1/5` `3/25` `1/10` `1/25` `1/25`

E(X2) = `1 xx 1/2 + 4 xx 1/5 + 16 xx 3/25 + 36 xx 1/10 + 81 xx 1/25 + 225 xx 1/25`

= `1/2 + 4/5 + 48/25 + 36/10 + 81/25 + 225/25`

= 0.5 + 0.8 + 1.92 + 3.6 + 3.24 + 9.00

= 19.06

Variance (X) = E(X2) – [E(X)]2

= 19.06 – (2.94)2

= 19.06 – 8.64

= 10.42

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पाठ 13: Probability - Exercise [पृष्ठ २७८]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 13 Probability
Exercise | Q 50.(ii) | पृष्ठ २७८

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Solution:

Here, n = 4

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∴ q = 1 - p = 1 - 0.1 = `square`

X ∼ B(4, 0.1)

 `P(X=x)=""^n"C"_x p^x q^(n-x)= ""^4"C"_x (0.1)^x (0.9)^(4 - x)`

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