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Find the Probability Distribution Of Number of Tails in the Simultaneous Tosses of Three Coins - Mathematics and Statistics

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प्रश्न

Find the probability distribution of number of tails in the simultaneous tosses of three coins.

बेरीज

उत्तर

When three coins are tossed simultaneously, the sample space is

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Let X represent the number of tails.

It can be seen that X can take the value of 0, 1, 2 or 3

P(X = 0) = P(HHH) = `1/8`

P(X = 1) = P(HHT) + P(HTH) + P(THH) =`1/8 +1/8+1/8 =3/8`

P(X = 2) = P(HTT) + P(THT) + P(TTH) =`1/8+1/8+1/8 = 3/8`

P(X = 3) = P(TTT) = `1/8`

Thus, the probability distribution is as follows.

X 0 1 2 3
P(X) `1/8` `3/8` `3/8` `1/8`
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पाठ 13: Probability - Exercise 13.4 [पृष्ठ ५७०]

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एनसीईआरटी Mathematics [English] Class 12
पाठ 13 Probability
Exercise 13.4 | Q 4.2 | पृष्ठ ५७०
बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
पाठ 7 Probability Distributions
Exercise 7.1 | Q 4. (ii) | पृष्ठ २३२

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A large chain retailer purchases an electric device from the manufacturer. The manufacturer indicates that the defective rate of the device is 10%. The inspector of the retailer randomly selects 4 items from a shipment. Complete the following activity to find the probability that the inspector finds at most one defective item in the 4 selected items.

Solution:

Here, n = 4

p = probability of defective device = 10% = `10/100 = square`

∴ q = 1 - p = 1 - 0.1 = `square`

X ∼ B(4, 0.1)

 `P(X=x)=""^n"C"_x p^x q^(n-x)= ""^4"C"_x (0.1)^x (0.9)^(4 - x)`

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= `square+square`

∴ P[X ≤ 1] = `square`


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