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प्रश्न
Two particles P and Q of mass 1 kg and 3 kg respectively start moving towards each other from rest under mutual attraction. What is the velocity of their center of mass?
उत्तर
Given,
Mass of particle P = 1 kg Mass of particle Q = 3 kg
Solution:
Particles P and Q form a system. Here no external force is acting on the system,
We know that M = `d/dt` (VCM ) = f
It means that C.M. of an isolated system remains at rest when no external force is acting and internal forces do not change its center of mass.
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