Advertisements
Advertisements
प्रश्न
Use tables to find cosine of 26° 32’
उत्तर
cos 26° 32’ = cos (26° 30’ + 2’)
= 0.8949 − 0.0003
= 0.8946
APPEARS IN
संबंधित प्रश्न
`(\text{i})\text{ }\frac{\cot 54^\text{o}}{\tan36^\text{o}}+\frac{\tan 20^\text{o}}{\cot 70^\text{o}}-2`
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°
Show that cos 38° cos 52° − sin 38° sin 52° = 0
Solve.
`cos55/sin35+cot35/tan55`
Evaluate.
`cos^2 26^@+cos65^@sin26^@+tan36^@/cot54^@`
Find the value of x, if tan x = `(tan60^circ - tan30^circ)/(1 + tan60^circ tan30^circ)`
Find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° – 3A) . cosec 42° = 1
Use tables to find the acute angle θ, if the value of cos θ is 0.9574
A, B and C are interior angles of a triangle ABC. Show that
sin `(("B"+"C")/2) = cos "A"/2`
Find the value of the following:
tan 15° tan 30° tan 45° tan 60° tan 75°