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What is the ratio of maxmimum acceleration to the maximum velocity of a simple harmonic oscillator? - Physics

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प्रश्न

What is the ratio of maxmimum acceleration to the maximum velocity of a simple harmonic oscillator?

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उत्तर

Let x = A sin ω is the displacement function of SHM.

Velocity, `v = (dx)/(dt) = Aω cosωt`

`v_max = Aω |cos ωt|_"max"`

= `Aω xx 1`

= `ωA`    [∵ |cos ωt|max = 1] ......(i)

Acceleration, `a = (dv)/(dt) = - ωA * ωsinωt`

= `- ω^2A sinωt`

`|a_max| = |(- ω^2A)(+1)|`   ......[∵ (sin ωt)max = 1]

`|a_max| = ω^2A`  .......(ii)

From equations (i) and (ii), we get

`v_max/a_max = (ωA)/(ω^2A) = 1/ω`

⇒ `a_max/v_max = ω`

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पाठ 14: Oscillations - Exercises [पृष्ठ १०२]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 14 Oscillations
Exercises | Q 14.23 | पृष्ठ १०२

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