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प्रश्न
When D-glucose reacts with HI, it forms ______.
पर्याय
Gluconic acid
n-hexane
Saccharic acid
Iodohexane
उत्तर
When D-glucose reacts with HI, it forms n-hexane.
Explanation:
On prolonged heating with HI, it forms n-hexane, suggesting that all the six carbon atoms are linked in a straight chain.
\[\begin{array}{cc}
\ce{CHO}\phantom{.................................................}\\
|\phantom{.....................................................}\\
\ce{(CHOH)4 ->[HI,\Delta] \underset{{(n-Hexane)}}{CH3 - CH2 - CH2 - CH2 - CH2 - CH3}}\\
|\phantom{.....................................................}\\
\ce{CH2OH}\phantom{...............................................}
\end{array}\]
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संबंधित प्रश्न
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
Differentiable between the following:
Amylose and Amylopectin
Write the reactions involved when D-glucose is treated with the following reagent:
Br2 water
Glucose does not give Schiff’s test because of the formation of cyclic ____________.
Which of the following reactions of glucose can be explained only by its cyclic structure?
Which of the following pairs represents anomers?
Write the reactions of D-glucose which can’t be explained by its open-chain structure. How can cyclic structure of glucose explain these reactions?
Account for the following:
What happens when D – glucose is treated with the following reagents
HNO3
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
Match List - I with List - II.
| List I | List II | ||
| (A) | Glucose + HI | (I) | Gluconic acid |
| (B) | Glucose + Br2 water | (II) | Glucose pentacetate |
| (C) | Glucose + acetic anhydride | (III) | Saccharic acid |
| (D) | Glucose + HNO3 | (IV) | Hexane |
Choose the correct answer from the options given below:
