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प्रश्न
Write the sum of intercepts cut off by the plane `vecr.(2hati+hatj-k)-5=0` on the three axes
उत्तर
`vecr.(2hati+hatj-k)-5=0`
in Cartesian form
2x + y - z - 5=0
2x + y - z = 5
`(2x)/5+y/5-z/5=1`
`x/"5/2"+y/5+z/(-5)=1`
Intercept cutt of on the axes `(5/2,5,-5)`
`x/a+y/b+z/c=1`
`a=5/2 ` b = 5 c = -5
a + b + c = 5 /2
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