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Question
A and B are two points on the x-axis and y-axis respectively.
- Write down the coordinates of A and B.
- P is a point on AB such that AP : PB = 1 : 1.
Using section formula find the coordinates of point P. - Find the equation of a line passing through P and perpendicular to AB.
Solution
a. Coordinates of A are (4, 0)
and coordinates of B are (0, 4)
b. AP : PB = 3 : 1
i.e.
Coordinates of P are
`((m_1x_2 + m_2x_1)/(m_1 + m_2), (m_1y_2 + m_2y_1)/(m_1 + m_2))`
= `((3 xx 0 + 1 xx 4)/(3 + 1), (3 xx 4 + 1 xx 0)/(3 + 1))`
= `(4/4, 12/4)`
= (1, 3)
c. Slope of A = `(y_2 - y_1)/(x_2 - x_1)`
= `(4 - 0)/(0 - 4)`
= – 1
∴ Slope of the line perpendicular to AB
m = 1
Equation of line perpendicular to AB and passing through P(1, 3) is
y – y1 = m(x – x1)
`\implies` y – 3 = 1(x – 1)
`\implies` y – 3 = x – 1
`\implies` x – y + 2 = 0
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