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Karnataka Board PUCPUC Science 2nd PUC Class 12

A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line? - Physics

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Question

A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line?

Numerical

Solution

Current in the power line, I = 90 A

Point is located below the power line at distance, r = 1.5 m

Hence, magnetic field at that point is given by the relation,

B = μ02I4πr

Where,

μ0 = Permeability of free space = 4π × 10–7 T m A–1

B = 4π×10-7×2×904π×1.5

= 1.2 × 10–5 T

The current is flowing from East to West. The point is below the power line. Hence, according to Maxwell’s right-hand thumb rule, the direction of the magnetic field is towards the South.

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Chapter 4: Moving Charges and Magnetism - Exercise [Page 169]

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NCERT Physics [English] Class 12
Chapter 4 Moving Charges and Magnetism
Exercise | Q 4.4 | Page 169
NCERT Physics [English] Class 12
Chapter 4 Moving Charges and Magnetism
Exercise 2 | Q 4 | Page 169

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