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Question
If A and B be mutually exclusive events associated with a random experiment such that P(A) = 0.4 and P(B) = 0.5, then find
\[P (\bar{ A } \cap \bar{ B} )\]
Solution
Given:
P(A) = 0.4 and P(B) = 0.5
If A and B be mutually exclusive event, then P (A ∩ B) = 0
\[P\left( \bar{A} \cap B \right) = 1 - P\left( A \cup B \right)\]
= 1 - 0.9 = 0.1
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