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Given Two Mutually Exclusive Events a and B Such that P(A) = 1/2 and P(B) = 1/3, Find P (A Or B). - Mathematics

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Question

Given two mutually exclusive events A and B such that P(A) = 1/2 and P(B) = 1/3, find P(A or B).

Solution

Given:
P(A) = 1/2 and P(B) = 1/3
For mutually exclusive events A and B, we have:
P(A or B) = P(A) + P(B)

\[= \frac{1}{2} + \frac{1}{3} = \frac{3 + 2}{6} = \frac{5}{6}\]

Hence,

\[P\left( A \text{ or }  B \right) = \frac{5}{6}\]
 
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Chapter 33: Probability - Exercise 33.4 [Page 68]

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RD Sharma Mathematics [English] Class 11
Chapter 33 Probability
Exercise 33.4 | Q 5 | Page 68

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