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Question
A random variable X has the following probability mass function.
| x | 1 | 2 | 3 | 4 | 5 |
| F(x) | k2 | 2k2 | 3k2 | 2k | 3k |
Find P(X > 3)
Solution
P(X > 3) = P(X = 4) + P(X = 5)
= `2/6 + 3/6`
= `5/6`
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